# Advantages of Bohr’s Theory

(i) Bohr’s theory satisfactorily explains the spectra of species having one electron, viz. hydrogen atom, He^{+}, Li^{2+} etc.

(ii) Calculation of radius of Bohr’s orbit: According to Bohr, radius of nth orbit in which electron moves is r_{n} = [h^{2}/4π^{2}me^{2}k] n^{2}/Z

Where, n = Orbit number, m = Mass number [9.1×10^{-31}kg],e = Charge on the electron [1.6×10^{-19}] Z = Atomic number of element, k = Coulombic constant [9×10^{9}Nm^{2}c^{-2}] After putting the values of m,e,k,h, we get. r_{n} = n^{2}/Z×0.529Å

(iii) Calculation of velocity of electron V_{n} = 2πe^{2}ZK/nh, V_{n} = [Ze^{2}/mr]^{1/2}; V_{n} = 2.188×10^{8}Z/n (cm.sec^{-1})

(iv) Calculation of energy of electron in Bohr’s orbit

Total energy of electron = K.E. + P.E. of electron = k Ze^{2}/2r - kZe^{2}/r = kZe^{2}/2r

Substituting of r, gives us E = (-2π^{2}mZ^{2}e^{4}k^{2}/n^{2}h^{2}) Where, n=1, 2, 3……….∞

Putting the value of m, e, k, h, π we get

When an electron jumps from an outer orbit (higher energy) n_{2} to an inner orbit (lower energy)n_{1}, then the energy emitted in form of radiation is given by

Where, R = 2π^{2}K^{2}me^{4}/ch^{3} R is known as Rydberg constant. Its value to be used is 109678cm^{-1}

The negative sign in the above equations shows that the electron and nucleus form a bound system, i.e., the electron is attracted towards the nucleus. Thus, if electron is to be taken away from the nucleus, energy has to be supplied. The energy of the electron in n = 1 orbit is called the ground state energy; that in the n = 2 orbit is called the first excited state energy, etc. When n = ∞ then E = 0 which corresponds to ionized atom i.e., the electron and nucleus are infinitely separated H → H^{+} + e^{-} (ionization).